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Question 28 of 43

Q.The general solution of the differential equation dydx=cos⁡x\frac{dy}{dx}=\cos x is :

(a) y=sin⁡x−2y=\sin x-2
(b) y=cos⁡x+cy=\cos x+c, cc is an arbitrary constant
(c) y=sin⁡x+1y=\sin x+1
(d) y=sin⁡x+cy=\sin x+c, cc is an arbitrary constant
Puducherry TnboardTamil Nadu HSC (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
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y=∫cos⁡x dx=sin⁡x+cy=\int\cos x\,dx=\sin x+c.

Separating and integrating dydx=cos⁡x\dfrac{dy}{dx}=\cos x:

y=∫cos⁡x dx=sin⁡x+c,y=\int\cos x\,dx=\sin x+c,

where cc is an arbitrary constant (a first-order equation's general solution must contain one arbitrary constant). Options with fixed …

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