Q.Write the rate law for the reaction in which the order with respect to the reactants X, Y and Z are $1/2$, $3/2$ and zero respectively.

The rate law is written as the rate constant multiplied by each reactant's concentration raised to its own order; since Z has order zero, its concentration term simply drops out (any quantity to the power zero is 1).

The rate law for a reaction expresses the rate as proportional to the concentration of each reactant, each raised to the power of its individual order of reaction with respect to that reactant: $\text{Rate} = k[X]^{n_X}[Y]^{n_Y}[Z]^{n_Z}$ Given $n_X = 1/2$, $n_Y = 3/2$, $n_Z = 0$: $\text{Rate} = k[X]^{1/2}[Y]^{3/2}[Z]^0 = k[X]^{1/2}[Y]^{3/2}$ (since $[Z]^0 = 1$, Z's concentration has no effect on the rate, even though it may still be a genuine participant in the overall …