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Choose the Best Answer · Q1

Q.The sum of primary valence and secondary valence of the metal M in the complex [M(en)₂(Ox)]Cl is

(a) 3
(b) 6
(c) -3
(d) 9
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✓ Free question

Step 1. [M(en)₂(Ox)]Cl has a Cl⁻ counter ion outside the bracket, so the complex ion [M(en)₂(Ox)] carries a +1 charge.

Step 2. en is a neutral bidentate ligand (charge 0, two N donor atoms each); Ox (oxalate) is an anionic bidentate ligand (charge -2, two O donor atoms).

Step 3. Charge balance: x + 2(0) + 1(-2) = +1, so x = +3. This is the primary valence (oxidation state, per Werner) of M.

Step 4. Secondary valence = coordination number = total donor atoms = 2 en × 2 + 1 Ox × 2 = 4 + 2 = 6.

Step 5. Sum of primary and secondary valence = 3 + 6 = 9.

✓Final answer

(d) 9

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