Question 47 of 50
Q.(i) Calculate the oxidation number of central metal atom of the following complex compound: [Cr(NH3)5Cl]SO4.
(ii) When aqueous solution of one mole of CrCl3.6H2O complex compound is treated with excess of AgNO3, 3 moles of AgCl are precipitated. Determine the formula of the complex compound. [1+1]
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2024Subjective· 2mImportance★★★★★
94% · 47/50 Questions
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Start your 14-day free trial to unlock the full solution →Balancing charges gives Cr = +3 in the ammine-chloro complex; all-Cl-precipitated-by-AgNO means the formula is the hexaaqua complex with 3 ionisable chlorides.
(i) Oxidation number of Cr in [Cr(NH)Cl]SO:
NH is a neutral ligand (charge 0), Cl within the coordination sphere carries −1, and SO is the counter-ion outside the sphere, balancing a +2 charge on the complex ion [Cr(NH)Cl].
Let oxidation number of Cr = :
(ii) Formula from the AgNO precipitation: …
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