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Choose the Best Answer · Q2

Q.An excess of silver nitrate is added to 100 ml of a 0.01 M solution of pentaaquachloridochromium(III) chloride. The number of moles of AgCl precipitated would be

(a) 0.02
(b) 0.002
(c) 0.01
(d) 0.2
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✓ Free question

Step 1. 'Pentaaquachloridochromium(III) chloride' names the complex [Cr(H₂O)₅Cl]Cl₂: five aqua ligands and one chlorido ligand inside the coordination sphere (secondary valence 6, matching Cr(III)'s usual coordination number), with two Cl⁻ as the outer, ionisable counter ions.

Step 2. Moles of complex = Molarity × Volume = 0.01 mol/L × 0.100 L = 0.001 mol.

Step 3. Only the OUTER-sphere (ionisable) chlorides react with excess Ag⁺ to precipitate AgCl; the one Cl⁻ inside the coordination sphere is firmly bound and does not ionise (per Werner's postulate 4).

Step 4. Each mole of complex releases 2 mol of ionisable Cl⁻, so moles of AgCl precipitated = 0.001 × 2 = 0.002 mol.

✓Final answer

(b) 0.002

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