Choose the Best Answer · Q2
Q.An excess of silver nitrate is added to 100 ml of a 0.01 M solution of pentaaquachloridochromium(III) chloride. The number of moles of AgCl precipitated would be
(a) 0.02
(b) 0.002
(c) 0.01
(d) 0.2
Puducherry TnboardTextbookSubjectiveImportance★★★★★est
4% · 3/67 Questions
✓ Free question
Step 1. 'Pentaaquachloridochromium(III) chloride' names the complex [Cr(H₂O)₅Cl]Cl₂: five aqua ligands and one chlorido ligand inside the coordination sphere (secondary valence 6, matching Cr(III)'s usual coordination number), with two Cl⁻ as the outer, ionisable counter ions.
Step 2. Moles of complex = Molarity × Volume = 0.01 mol/L × 0.100 L = 0.001 mol.
Step 3. Only the OUTER-sphere (ionisable) chlorides react with excess Ag⁺ to precipitate AgCl; the one Cl⁻ inside the coordination sphere is firmly bound and does not ionise (per Werner's postulate 4).
Step 4. Each mole of complex releases 2 mol of ionisable Cl⁻, so moles of AgCl precipitated = 0.001 × 2 = 0.002 mol.
✓Final answer
(b) 0.002
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.