When nitromethane is reduced with $Zn/NH_4Cl$, we get : (a) $CH_3NH_2$ (b) $C_2H_5NH_2$ (c) $CH_3NHOH$ (d) $C_2H_5COOH$

When nitromethane is reduced with Zn/NH₄Cl, we get : (a) CH₃NH₂ (b) C₂H₅NH₂ (c) CH₃NHOH (d) C₂H₅COOH

Question 44 of 69

Zn/NH_4Cl

(a)

CH_3NH_2

(b)

C_2H_5NH_2

(c)

CH_3NHOH

(d)

C_2H_5COOH

Puducherry TnboardTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★

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Nitromethane with Zn/NH $_4$ Cl (neutral reducing conditions) is only partially reduced, stopping at N-methylhydroxylamine.

Complete reduction of a nitro compound (e.g. with Sn/HCl or Fe/HCl or H $_2$ /Ni) gives the primary amine, but Zn dust with NH $_4$ Cl solution is a classical mild, neutral-medium reducing system that arrests the reduction sequence $R-NO_2 \rightarrow R-NO \rightarrow R-NHOH \rightarrow R-NH_2$ at the intermediate N-substituted hydroxylamine stage. So $CH_3NO_2$ gives $CH_3NHOH$ (N-methylhydroxylamine), not the amine. Options (a) and (b …

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Q.When nitromethane is reduced with $Zn/NH_4Cl$ , we get :

Concept understanding — Reduction and Hydrolysis of Nitroalkanes

Q.When nitromethane is reduced with Zn/NH4ClZn/NH_4ClZn/NH4​Cl, we get :

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Q.When nitromethane is reduced with $Zn/NH_4Cl$ , we get :

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