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Question 63 of 68

Q.In an electrical field, the particles of a Colloidal system move towards cathode. The coagulation of the same sol is studied using

(i) K2SO4K_2SO_4,
(ii) Na3PO4Na_3PO_4,
(iii) K4[Fe(CN)6]K_4[Fe(CN)_6] and
(iv) NaCl. Their coagulating power should be :
(a)
(iii) >
(ii) >
(i) >
(iv)
(b)
(i) >
(ii) >
(iii) >
(iv)
(c)
(ii) >
(i) >
(iv) >
(iii)
(d) None of these
Puducherry TnboardTamil Nadu HSC (DGE) Board 2025MCQ· 1mImportance★★★★★
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Since the colloidal particles move to the cathode, the sol is positively charged, so coagulation requires oppositely-charged (anionic) electrolytes; the Hardy–Schulze rule states coagulating power increases sharply with the valency of the effective (oppositely-charged) ion, ranking [Fe(CN)6]4−[Fe(CN)_6]^{4-} highest and Cl−Cl^- lowest.

Step 1 — identify the charge on the sol: in electrophoresis, colloidal particles migrate towards the electrode of opposite charge. Since the particles move towards the cathode (the negative electrode), the particles themselves must be positively charged.

Step 2 — identify the effective coagulating ion: for a positively charged sol, coagulation is caused by the anion of the added electrolyte (the ion of charge opposite to the sol).

Step 3 — apply the Hardy–Schulze rule: the coagulating power of an ion increases sharply (not linearly) with its valency/charge. Identifying the anion and its charge in each electrolyte:

  • (i) K2SO4K_2SO_4 → SO42−SO_4^{2-} (charge −2-2)
  • (ii) Na3PO4Na_3PO_4 → PO43−PO_4^{3-} (charge −3-3) …

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