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Exercise 7.10 · Q10

Q.The value of the limit displaystylelimxto0left(cotx−dfrac1xright)\\displaystyle\\lim_{x\\to0}\\left(\\cot x-\\dfrac1x\\right) is

(1) 0
(2) 1
(3) 2
(4) ∞\infty
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Combine into a single fraction (an ∞−∞\infty-\infty form becomes 00\tfrac00), then apply l'Hôpital twice.

Step 1. Combine. cot⁡x−1x=cos⁡xsin⁡x−1x=xcos⁡x−sin⁡xxsin⁡x\cot x-\dfrac1x=\dfrac{\cos x}{\sin x}-\dfrac1x=\dfrac{x\cos x-\sin x}{x\sin x}, a 00\tfrac00 form at x=0x=0.

Step 2. Apply l'Hôpital once. …

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