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Exercise 7.10 · Q4

Q.A stone is thrown up vertically. The height it reaches at time tt seconds is given by x=80t−16t2x=80t-16t^2. The stone reaches the maximum height in time tt seconds is given by

(1) 2
(2) 2.5
(3) 3
(4) 3.5
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Maximum height occurs when the velocity (rate of change of height) is zero.

Step 1. Differentiate. x=80t−16t2⇒v(t)=80−32tx=80t-16t^2\Rightarrow v(t)=80-32t. …

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