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Exercise 7.10 · Q9

Q.Angle between y2=xy^2=x and x2=yx^2=y at the origin is

(1) tan⁡−134\tan^{-1}\dfrac34
(2) tan⁡−1(43)\tan^{-1}\left(\dfrac43\right)
(3) π2\dfrac{\pi}{2}
(4) π4\dfrac{\pi}{4}
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Determine each curve's tangent direction at the origin directly, rather than via a slope formula that breaks down at (0,0)(0,0).

Step 1. Tangent to y2=xy^2=x at the origin.

Writing x=y2x=y^2: dxdy=2y→0\dfrac{dx}{dy}=2y\to0 as y→0y\to0, so the tangent line is vertical (x=0x=0) at the origin.

Step 2. Tangent to x2=yx^2=y at the origin.

y=x2⇒dydx=2x→0y=x^2\Rightarrow\dfrac{dy}{dx}=2x\to0 as x→0x\to0, so the tangent line is horizontal (y=0y=0) at the origin. …

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