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Question 127 of 148

Q.Evaluate : lim⁡x→∞2x2−3x2−5x+3\displaystyle\lim_{x\to\infty}\dfrac{2x^2-3}{x^2-5x+3}

Puducherry TnboardTamil Nadu HSC (DGE) Board 2022Subjective· 3mImportance★★★★★
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Divides through by the highest power of x in the denominator so that all vanishing terms drop out as x tends to infinity.

  1. We need lim⁡x→∞2x2−3x2−5x+3\displaystyle\lim_{x\to\infty}\dfrac{2x^2-3}{x^2-5x+3}, an indeterminate ∞∞\dfrac{\infty}{\infty} form as stated, so divide numerator and denominator by the highest power of xx present, x2x^2. …

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