Skip to content
Question 103 of 148

Q.The slope of the tangent to the curve y=3x2+3sin⁡xy = 3x^2 + 3 \sin x at x=0x = 0 is :

(a) 11
(b) 33
(c) −1-1
(d) 22
Puducherry TnboardTamil Nadu HSC (DGE) Board 2018MCQ· 1mImportance★★★★★
70% · 103/148 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Differentiating y=3x2+3sin⁡xy=3x^2+3\sin x and evaluating at x=0x=0 gives slope 33.

  1. Differentiate term by term: ddx(3x2)=6x\dfrac{d}{dx}(3x^2)=6x and ddx(3sin⁡x)=3cos⁡x\dfrac{d}{dx}(3\sin x)=3\cos x.
  2. So y′=6x+3cos⁡xy' = 6x + 3\cos x.
  3. Substitute x=0x=0: y′(0)=6(0)+3cos⁡(0)=0+3(1)=3y'(0) = 6(0) + 3\cos(0) = 0 + 3(1) = 3. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.