Exercise 2.9 · Q7
Q.If , then the greatest value of is
(1)
(2)
(3)
(4)
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Start your 14-day free trial to unlock the full solution →By the triangle inequality, for any point in a disk centered at with radius , the farthest such can be from the origin is — reached at the point diametrically opposite the origin through the center.
Step 1. Rewrite the given condition in center–radius form.
So ranges over the closed disk with center and radius .
Step 2. Apply the triangle inequality to bound .
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