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Exercise 2.9 · Q4

Q.The conjugate of a complex number is 1i−2\dfrac1{i-2}. Then, the complex number is

(1) 1i+2\dfrac1{i+2}
(2) −1i+2\dfrac{-1}{i+2}
(3) −1i−2\dfrac{-1}{i-2}
(4) 1i−2\dfrac1{i-2}
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Taking the conjugate of both sides undoes the bar on the left and, using 1/z‾=1/z‾\overline{1/z}=1/\overline z, turns i−2i-2 into −i−2-i-2 on the right.

Step 1. Set up the equation. Let ww be the required complex number. We are told

w‾=1i−2.\overline{w}=\frac1{i-2}.

Step 2. Take the conjugate of both sides (using w‾‾=w\overline{\overline w}=w and 1/z‾=1/z‾\overline{1/z}=1/\overline z):

w=(1i−2)‾=1i−2‾=1−i−2.w=\overline{\left(\frac1{i-2}\right)}=\frac1{\overline{i-2}}=\frac1{-i-2}.

Step 3. Simplify the sign.

w=1−(i+2)=−1i+2.w=\frac1{-(i+2)}=\frac{-1}{i+2}.

Step 4. Rationalize to double-check numerically. Multiply numerator and denominator by the conjugate 2−i2-i:

w=−1i+2⋅2−i2−i=−(2−i)4+1=−2+i5=−25+15i.w=\frac{-1}{i+2}\cdot\frac{2-i}{2-i}=\frac{-(2-i)}{4+1}=\frac{-2+i}{5}=-\frac25+\frac15i. …

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