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Question 86 of 122

Q.If ∣z−z1∣=∣z−z2∣|z - z_1| = |z - z_2| then the locus of zz is :

(a) a straight line passing through the origin
(b) a circle with centre at the origin
(c) is a perpendicular bisector of the line joining z1z_1 and z2z_2
(d) a circle with centre at z1z_1
Puducherry TnboardTamil Nadu HSC (DGE) Board 2018MCQ· 1mImportance★★★★★
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The equation states that zz is equidistant from the fixed points z1z_1 and z2z_2, which is exactly the geometric definition of the perpendicular bisector of the segment z1z2z_1z_2.

  1. Interpret ∣z−z1∣|z-z_1| as the distance from the point zz to the fixed point z1z_1, and ∣z−z2∣|z-z_2| as the distance from zz to the fixed point z2z_2.
  2. The equation ∣z−z1∣=∣z−z2∣|z-z_1|=|z-z_2| says these two distances are always equal.
  3. The locus of points equidistant from two fixed points z1,z2z_1,z_2 is, by the standard geometric definition, the perpendicular bisector of the segment joining them. …

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