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Question 92 of 122

Q.If z1=1+2iz_1 = 1 + 2i, z2=1−3iz_2 = 1 - 3i and z3=2+4iz_3 = 2 + 4i then, the points on the Argand diagram representing z1z2z3z_1 z_2 z_3, 2z1z2z32z_1 z_2 z_3, −7z1z2z3-7z_1 z_2 z_3 are :

(a) Vertices of an isosceles triangle
(b) Collinear
(c) Vertices of a right angled triangle
(d) Vertices of an equilateral triangle
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The three points are real-number multiples of the same complex number z1z2z3z_1z_2z_3, so they are collinear.

  1. Compute z1z2=(1+2i)(1−3i)=1−3i+2i−6i2=1−i+6=7−iz_1z_2=(1+2i)(1-3i)=1-3i+2i-6i^2=1-i+6=7-i.
  2. Compute z1z2z3=(7−i)(2+4i)=14+28i−2i−4i2=14+26i+4=18+26iz_1z_2z_3=(7-i)(2+4i)=14+28i-2i-4i^2=14+26i+4=18+26i.
  3. Let w=z1z2z3=18+26iw=z_1z_2z_3=18+26i. The three given points are ww, 2w2w, and −7w-7w.
  4. Each of these is a real scalar multiple of the same complex number ww (multiples 1,2,−71,2,-7). …

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