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Question 111 of 122

Q.If (1+i)(1+2i)(1+3i)…(1+ni)=x+iy(1+i)(1+2i)(1+3i)\ldots(1+ni)=x+iy then 2⋅5⋅10…(1+n2)2\cdot5\cdot10\ldots(1+n^2) is :

(a) x2+y2x^2+y^2
(b) 11
(c) 1+n21+n^2
(d) ii
Puducherry TnboardTamil Nadu HSC (DGE) Board 2024MCQ· 1mImportance★★★★★
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Uses multiplicativity of the complex modulus on both sides of the given product, then squares to match x2+y2x^2+y^2.

  1. Given (1+i)(1+2i)(1+3i)⋯(1+ni)=x+iy(1+i)(1+2i)(1+3i)\cdots(1+ni)=x+iy.
  2. Take modulus of both sides: ∣1+i∣ ∣1+2i∣⋯∣1+ni∣=∣x+iy∣|1+i|\,|1+2i|\cdots|1+ni|=|x+iy|.
  3. Square both sides: ∣1+i∣2∣1+2i∣2⋯∣1+ni∣2=x2+y2|1+i|^2|1+2i|^2\cdots|1+ni|^2=x^2+y^2. …

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