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Exercise 8.1 · Q4

Q.The radius of a circular plate is measured as 12.6512.65 cm instead of the actual length 12.512.5 cm. Find the following in calculating the area of the circular plate:

(i) Absolute error
(ii) Relative error
(iii) Percentage error
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The actual radius is r0=12.5r_0=12.5 cm and the measured radius is 12.6512.65 cm, so the error in the radius is dr=0.15dr=0.15 cm; propagate this through A(r)=πr2A(r)=\pi r^2 using the differential dA=A′(r0) drdA=A'(r_0)\,dr.

Step 1. Identify the actual value and the increment. Actual radius r0=12.5r_0=12.5 cm, measured radius =12.65=12.65 cm, so dr=12.65−12.5=0.15dr=12.65-12.5=0.15 cm.

Step 2. Compute the differential of the area. A(r)=πr2⇒A′(r)=2πrA(r)=\pi r^2\Rightarrow A'(r)=2\pi r, so A′(r0)=2π(12.5)=25πA'(r_0)=2\pi(12.5)=25\pi.

dA=A′(r0) dr=25π(0.15)=3.75π cm2.dA = A'(r_0)\,dr = 25\pi(0.15) = 3.75\pi \text{ cm}^2.

This dAdA is the absolute error made in the calculated area, by Definition 8.2/equation (6).

Step 3. Absolute error. dA=3.75π≈11.781dA=3.75\pi\approx11.781 cm2^2. …

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