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Exercise 8.8 · Q8

Q.The change in the surface area S=6x2S=6x^2 of a cube when the edge length varies from x0x_0 to x0+dxx_0+dx is

(1) 12x0+dx12x_0+dx
(2) 12x0dx12x_0dx
(3) 6x0dx6x_0dx
(4) 6x0+dx6x_0+dx
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The CHANGE in surface area as the edge varies from x0x_0 to x0+dxx_0+dx is exactly the differential dS=S′(x0) dxdS=S'(x_0)\,dx.

Step 1. Differentiate S=6x2S=6x^2. S′(x)=12xS'(x)=12x. …

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