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Exercise 12.1 · Q7
Q.

Consider the binary operation ∗* defined on the set A={a,b,c,d}A=\{a,b,c,d\} by the following table:

∗*aabbccdd
aaaaccbbdd
bbddaabbcc
ccccddaaaa
ddddbbaacc

Is it commutative and associative?

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We read entries directly off the given Cayley table and compare a∗ba*b with b∗ab*a for commutativity, then compare (a∗b)∗c(a*b)*c with a∗(b∗c)a*(b*c) for associativity.

Step 1. Test commutativity with one pair. From the table, a∗b=ca*b=c (row aa, column bb) while b∗a=db*a=d (row bb, column aa). Since c≠dc\ne d, ∗* is not commutative.

Step 2. Test associativity with one triple. Compute (a∗b)∗c(a*b)*c: first a∗b=ca*b=c (from the table), then c∗c=ac*c=a (row cc, column cc). So (a∗b)∗c=a(a*b)*c=a. …

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