Exercise 12.1 · Q2
Q.On , define by . Is binary on ?
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✓ Free question
We look for one ordered pair of integers where fails to be an integer -- a single counterexample is enough to disprove closure.
Step 1. Try a pair with a negative exponent. Take .
Step 2. Compute . , and . So .
Step 3. Check membership. , so the output leaves for this pair -- condition (ii) of Definition 12.1 fails (the operation is not even defined as an integer here, let alone unique-in-).
Conclusion. Since there exists at least one pair for which , is not a binary operation on .
✓Final answer
No, is not binary on . Counterexample: .
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