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Exercise 12.1 · Q1

Q.Determine whether ∗* is a binary operation on the sets given below.

(i) a∗b=a⋅∣b∣a*b = a\cdot|b| on R\mathbb{R}
(ii) a∗b=min⁡(a,b)a*b = \min(a,b) on A={1,2,3,4,5}A=\{1,2,3,4,5\}
(iii) (a∗b)=ab(a*b) = a\sqrt{b} is binary on R\mathbb{R}.
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We test each rule against the two conditions of Definition 12.1: is the output defined for every ordered pair, and does it always land back inside the given set?

Step 1. Part (i): a∗b=a⋅∣b∣a*b=a\cdot|b| on R\mathbb R. For any a,b∈Ra,b\in\mathbb R, ∣b∣|b| is a well-defined non-negative real number, and a⋅∣b∣a\cdot|b| is the product of two real numbers -- always a single, well-defined real number. So a∗ba*b is defined for every pair and always lands in R\mathbb R.

Conclusion (i). ∗* is a binary operation on R\mathbb R.

Step 2. Part (ii): a∗b=min⁡(a,b)a*b=\min(a,b) on A={1,2,3,4,5}A=\{1,2,3,4,5\}. For any a,b∈Aa,b\in A, min⁡(a,b)\min(a,b) is simply the smaller of the two numbers (or either one, if equal) -- and since both a,b∈Aa,b\in A, the smaller of the two is also in AA (e.g. min⁡(2,5)=2∈A\min(2,5)=2\in A).

Conclusion (ii). ∗* is a binary operation on AA.

Step 3. Part (iii): (a∗b)=ab(a*b)=a\sqrt b on R\mathbb R. This requires b\sqrt b to be a real number, which fails whenever b<0b<0 (e.g. b=−4⇒−4b=-4\Rightarrow\sqrt{-4} is not real). Take a=1,b=−4∈R×Ra=1,b=-4\in\mathbb R\times\mathbb R: a∗b=1⋅−4a*b=1\cdot\sqrt{-4} is not defined in R\mathbb R at all -- condition (i) of Definition 12.1 already fails.

Conclusion (iii). ∗* is not a binary operation on R\mathbb R.

✓Final answer

(i) Yes, binary on R\mathbb R. (ii) Yes, binary on AA. (iii) No, not binary on R\mathbb R (fails for b<0b<0).

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