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Question 92 of 126

Q.The integrating factor of the differential equation dydx−ytan⁡x=cos⁡x\dfrac{dy}{dx} - y\tan x = \cos x is :

(a) sec⁡x\sec x
(b) cos⁡x\cos x
(c) etan⁡xe^{\tan x}
(d) cot⁡x\cot x
Puducherry TnboardTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★
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Identify the equation as first-order linear dydx+Py=Q\frac{dy}{dx}+Py=Q with P=−tan⁡xP=-\tan x, then compute I.F.=e∫P dx\text{I.F.}=e^{\int P\,dx}, using ∫tan⁡x dx=ln⁡∣sec⁡x∣\int\tan x\,dx=\ln|\sec x| and simplifying e−ln⁡∣sec⁡x∣=cos⁡xe^{-\ln|\sec x|}=\cos x.

  1. Given: dydx−ytan⁡x=cos⁡x\dfrac{dy}{dx} - y\tan x = \cos x.
  2. This is in the standard linear form dydx+Py=Q\dfrac{dy}{dx} + Py = Q, with P=−tan⁡xP = -\tan x and Q=cos⁡xQ=\cos x.
  3. The integrating factor is I.F.=e∫P dx=e∫(−tan⁡x) dx=e−∫tan⁡x dx\text{I.F.} = e^{\int P\,dx} = e^{\int(-\tan x)\,dx} = e^{-\int\tan x\,dx}. …

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