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Question 113 of 126

Q.Solve : dydx=1−y21−x2\dfrac{dy}{dx}=\dfrac{\sqrt{1-y^2}}{\sqrt{1-x^2}}

Puducherry TnboardTamil Nadu HSC (DGE) Board 2022Subjective· 2mImportance★★★★★
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Separates variables and integrates both sides using the standard inverse-sine integral.

  1. Given dydx=1−y21−x2\dfrac{dy}{dx}=\dfrac{\sqrt{1-y^2}}{\sqrt{1-x^2}}.
  2. Separate the variables: dy1−y2=dx1−x2\dfrac{dy}{\sqrt{1-y^2}}=\dfrac{dx}{\sqrt{1-x^2}}.
  3. Integrate both sides: ∫dy1−y2=∫dx1−x2\displaystyle\int\dfrac{dy}{\sqrt{1-y^2}}=\int\dfrac{dx}{\sqrt{1-x^2}}. …

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