Skip to content
Question 126 of 126

Q.Determine the order and degree (if exists) of the differential equation x2d2ydx2+[1+(dydx)2]1/2=0x^2\dfrac{d^2y}{dx^2}+\left[1+\left(\dfrac{dy}{dx}\right)^2\right]^{1/2}=0

Puducherry TnboardTamil Nadu HSC (DGE) Board 2026Subjective· 2mImportance★★★★★
100% · 126/126 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Removes the fractional power by squaring both sides, then reads off the order (highest derivative) and degree (its power) from the resulting polynomial equation.

  1. Given: x2d2ydx2+[1+(dydx)2]1/2=0x^2\dfrac{d^2y}{dx^2}+\left[1+\left(\dfrac{dy}{dx}\right)^2\right]^{1/2}=0.
  2. Order is the order of the highest derivative present, which is d2ydx2\dfrac{d^2y}{dx^2} (second derivative), so order =2=2.
  3. Degree is defined only once the equation is a polynomial in the derivatives (no fractional powers or radicals of derivatives). Currently the term [1+(y′)2]1/2\left[1+(y')^2\right]^{1/2} has a fractional power, so we must first clear it. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.