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Question 95 of 126

Q.The order and degree of the differential equation y′+(y′′)2=(x+y′′)2y' + (y'')^2 = (x + y'')^2 are :

(a) 2, 1
(b) 1, 1
(c) 2, 2
(d) 1, 2
Puducherry TnboardTamil Nadu HSC (DGE) Board 2018MCQ· 1mImportance★★★★★
75% · 95/126 Questions
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After cancelling the (y′′)2(y'')^2 terms on both sides, the equation reduces to one containing y′′y'' to the first power, so order = 2 and degree = 1.

  1. Expand the right-hand side: (x+y′′)2=x2+2xy′′+(y′′)2(x+y'')^2 = x^2 + 2xy'' + (y'')^2.
  2. Substitute into the given equation: y′+(y′′)2=x2+2xy′′+(y′′)2y' + (y'')^2 = x^2 + 2xy'' + (y'')^2.
  3. Cancel (y′′)2(y'')^2 from both sides: y′=x2+2xy′′y' = x^2 + 2xy''.
  4. Rearranged: 2xy′′−y′+x2=02xy'' - y' + x^2 = 0. This is now a polynomial equation in the derivatives, free of radicals/fractions involving them. …

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