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Exercise 11.5 · Q5

Q.A retailer purchases a certain kind of electronic device from a manufacturer. The manufacturer indicates that the defective rate of the device is 5%5\%. The inspector of the retailer randomly picks 1010 items from a shipment. What is the probability that there will be

(i) at least one defective item
(ii) exactly two defective items?
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X=X= number of defective items among 1010, with defective probability p=0.05⇒X∼B(10,0.05)p=0.05\Rightarrow X\sim B(10,0.05); (i) uses the complement of zero defectives,

(ii) is a direct pmf substitution.

Step 1. Identify the distribution. n=10, p=0.05, q=0.95n=10,\ p=0.05,\ q=0.95; X∼B(10,0.05)X\sim B(10,0.05).

Step 2. (i) At least one defective — complement rule. P(X≥1)=1−P(X=0)=1−(0.95)10P(X\ge1)=1-P(X=0)=1-(0.95)^{10}. Since (0.95)10≈0.5987(0.95)^{10}\approx0.5987, P(X≥1)≈1−0.5987=0.4013P(X\ge1)\approx1-0.5987=0.4013. …

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