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Exercise 11.5 · Q8

Q.If X∼B(n,p)X\sim B(n,p) is such that 4P(X=4)=P(X=2)4P(X=4)=P(X=2) and n=6n=6, find the distribution, mean and standard deviation of XX.

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Write both probabilities via the binomial pmf, cancel the common (6x)\binom6x-independent factors, and solve the resulting relation between pp and qq; then apply the standard mean/variance formulas.

Step 1. Write both probabilities. P(X=4)=(64)p4q2=15p4q2P(X=4)=\dbinom64p^4q^2=15p^4q^2 and P(X=2)=(62)p2q4=15p2q4P(X=2)=\dbinom62p^2q^4=15p^2q^4.

Step 2. Apply the given relation. 4P(X=4)=P(X=2)⇒4(15p4q2)=15p2q4⇒4p4q2=p2q44P(X=4)=P(X=2)\Rightarrow4(15p^4q^2)=15p^2q^4\Rightarrow4p^4q^2=p^2q^4.

Step 3. Simplify. Dividing both sides by p2q2p^2q^2 (both positive): 4p2=q2⇒q=2p4p^2=q^2\Rightarrow q=2p (taking the positive root, since p,q>0p,q>0).

Step 4. Solve using p+q=1p+q=1. p+2p=1⇒3p=1⇒p=13, q=23p+2p=1\Rightarrow3p=1\Rightarrow p=\dfrac13,\ q=\dfrac23.

Step 5. State the distribution. X∼B ⁣(6,13)X\sim B\!\left(6,\dfrac13\right): f(x)=(6x)(13)x(23)6−xf(x)=\dbinom6x\left(\dfrac13\right)^x\left(\dfrac23\right)^{6-x}. …

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