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Question 61 of 105

Q.20% of the bolts produced in a factory are found to be defective. Find the probability that in a sample of 10 bolts chosen at random exactly 2 will be defective using :

(i) Binomial distribution
(ii) Poisson distribution [e−2=0.1353e^{-2}=0.1353]
Puducherry TnboardTamil Nadu HSC (DGE) Board 2016Subjective· 6mImportance★★★★★
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Compute P(X=2)P(X=2) exactly with the binomial formula, then approximate it with the Poisson formula using λ=np\lambda=np.

Given: n=10n=10 bolts, probability of defective p=0.20p=0.20, so q=0.80q=0.80.

  1. Binomial distribution. P(X=r)=(nr)prqn−rP(X=r)=\binom{n}{r}p^r q^{n-r} For r=2r=2: P(X=2)=(102)(0.2)2(0.8)8P(X=2)=\binom{10}{2}(0.2)^2(0.8)^8 (102)=45\binom{10}{2}=45. Also (0.2)2=0.04(0.2)^2=0.04, and (0.8)8(0.8)^8: 0.82=0.640.8^2=0.64, 0.84=0.642=0.40960.8^4=0.64^2=0.4096, 0.88=0.40962=0.167772160.8^8=0.4096^2=0.16777216. P(X=2)=45×0.04×0.16777216=45×0.0067108864≈0.30199P(X=2)=45\times0.04\times0.16777216=45\times0.0067108864\approx0.30199
  2. Poisson approximation. For large nn and small pp, the binomial is approximated by a Poisson distribution with λ=np\lambda=np: …

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