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Question 66 of 105

Q.A continuous random variable X has p.d.f. f(x)f(x), then :

(a) 0≤f(x)≤10 \le f(x) \le 1
(b) f(x)≥0f(x) \ge 0
(c) f(x)≤1f(x) \le 1
(d) 0<f(x)<10 < f(x) < 1
Puducherry TnboardTamil Nadu HSC (DGE) Board 2017MCQ· 1mImportance★★★★★
63% · 66/105 Questions
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Recall the defining axioms of a probability density function: non-negativity everywhere, and total area 1 — there is no requirement that f(x)≤1f(x)\le1, since density values can exceed 1 for narrow distributions.

  1. By definition, a function f(x)f(x) is a probability density function (p.d.f.) of a continuous random variable XX if and only if:
    1. f(x)≥0f(x)\ge 0 for all x∈Rx\in\mathbb R, and
    2. ∫−∞∞f(x) dx=1\displaystyle\int_{-\infty}^{\infty} f(x)\,dx = 1. …

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