Skip to content
Question 96 of 105

Q.Suppose that X takes on one of the values 0, 1 and 2. If for some constant k, P(X=i)=k P(X=i−1)P(X=i)=k\,P(X=i-1) for i=1,2i=1,2 and P(X=0)=17P(X=0)=\dfrac17, then the value of k is :

(a) 33
(b) 11
(c) 44
(d) 22
Puducherry TnboardTamil Nadu HSC (DGE) Board 2025MCQ· 1mImportance★★★★★
91% · 96/105 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Building all three probabilities in terms of kk from the given recursive relation and using ∑P(X=i)=1\sum P(X=i)=1 gives a quadratic in kk, of which only the positive root is valid.

  1. Given P(X=0)=17P(X=0)=\dfrac17.
  2. For i=1i=1: P(X=1)=k P(X=0)=k7P(X=1)=k\,P(X=0)=\dfrac k7.
  3. For i=2i=2: P(X=2)=k P(X=1)=k⋅k7=k27P(X=2)=k\,P(X=1)=k\cdot\dfrac k7=\dfrac{k^2}7.
  4. Since XX only takes values 0,1,20,1,2, the probabilities must sum to 11: 17+k7+k27=1\dfrac17+\dfrac k7+\dfrac{k^2}7=1. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.