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Exercise 3.1 · Q8

Q.If α,β,γ,\alpha,\beta,\gamma, and δ\delta are the roots of the polynomial equation 2x4+5x3−7x2+8=02x^4+5x^3-7x^2+8=0, find a quadratic equation with integer coefficients whose roots are α+β+γ+δ\alpha+\beta+\gamma+\delta and αβγδ\alpha\beta\gamma\delta.

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Step 1. Read off the needed Vieta sums. For 2x4+5x3−7x2+0x+8=02x^4+5x^3-7x^2+0x+8=0: Σ1=−52\Sigma_1=-\dfrac52 and Σ4=82=4\Sigma_4=\dfrac82=4.

Step 2. These two numbers ARE the required new roots. The new quadratic's roots are r1=Σ1=−52r_1=\Sigma_1=-\tfrac52 and r2=Σ4=4r_2=\Sigma_4=4. …

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