The nuclei ${}_{13}Al^{27}$ and ${}_{14}Si^{28}$ are examples of : (a) isotopes (b) isobars (c) isotones (d) isomers

> [!TLDR] > Aluminium-27 and Silicon-28 both contain 14 neutrons, so they are isotones of each other. > > Nuclei are classified by comparing their proton number (atomic number $Z$), mass number $A$, and neutron number $N = A - Z$: > - **Isotopes**: same $Z$ (same element), different $A$ (different $N$). > - **Isobars**: same $A$, different $Z$ (and hence different $N$). > - **Isotones**: same $N$ (same number of neutrons), different $Z$ and $A$. > - **Isomers**: same $Z$ and $A$, but different nuclear energy states. > > For $_{13}Al^{27}$: $Z = 13$, $A = 27$, so $N = A - Z = 27 - 13 = 14$. > > For $_{14}Si^{28}$: $Z = 14$, $A = 28$, so $N = A - Z = 28 - 14 = 14$. > …

The nuclei ₁₃Al²⁷ and ₁₄Si²⁸ are examples of : (a) isotopes (b) isobars (c) isotones (d) isomers

Question 77 of 127

{}_{13}Al^{27}

(a) isotopes

(b) isobars

(d) isomers

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Aluminium-27 and Silicon-28 both contain 14 neutrons, so they are isotones of each other.

Nuclei are classified by comparing their proton number (atomic number $Z$ ), mass number $A$ , and neutron number $N = A - Z$ :

Isotopes: same $Z$ (same element), different $A$ (different $N$ ).
Isobars: same $A$ , different $Z$ (and hence different $N$ ).
Isotones: same $N$ (same number of neutrons), different $Z$ and $A$ .
Isomers: same $Z$ and $A$ , but different nuclear energy states.

For $_{13}Al^{27}$ : $Z = 13$ , $A = 27$ , so $N = A - Z = 27 - 13 = 14$ .

For $_{14}Si^{28}$ : $Z = 14$ , $A = 28$ , so $N = A - Z = 28 - 14 = 14$ .

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Q.The nuclei ${}_{13}Al^{27}$ and ${}_{14}Si^{28}$ are examples of :

Concept understanding — Isotopes Isobars Isotones

Q.The nuclei 13Al27{}_{13}Al^{27}13​Al27 and 14Si28{}_{14}Si^{28}14​Si28 are examples of :

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Q.The nuclei ${}_{13}Al^{27}$ and ${}_{14}Si^{28}$ are examples of :

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