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I. Multiple Choice Questions · Q7

Q.In a transformer, the number of turns in the primary and the secondary are 410 and 1230 respectively. If the current in primary is 6A, then that in the secondary coil is

(a) 2 A
(b) 18 A
(c) 12 A
(d) 1 A
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Step 1. The turns ratio is NS/NP=1230/410=3N_S/N_P = 1230/410 = 3.

Step 2. For an ideal transformer, IP/IS=NS/NPI_P/I_S = N_S/N_P, so IS=IP×(NP/NS)=IP/3I_S = I_P\times(N_P/N_S) = I_P/3.

Step 3. Substituting IP=6I_P=6 A: IS=6/3=2I_S = 6/3 = 2 A. …

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