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I. Multiple Choice Questions · Q10

Q.In a series RL circuit, the resistance and inductive reactance are the same. Then the phase difference between the voltage and current in the circuit is

(a) π4\dfrac{\pi}{4}
(b) π2\dfrac{\pi}{2}
(c) π6\dfrac{\pi}{6}
(d) zero
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Step 1. For a series RL circuit, the phase angle between voltage and current satisfies tan⁡ϕ=XL/R\tan\phi = X_L/R.

Step 2. Given R=XLR=X_L, this becomes tan⁡ϕ=XL/R=1\tan\phi = X_L/R = 1.

Step 3. Since tan⁡(π/4)=tan⁡45∘=1\tan(\pi/4)=\tan45^{\circ}=1, the phase angle is ϕ=π/4\phi=\pi/4. …

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