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Question 126 of 132

Q.In a transformer, the number of turns in the primary and the secondary are 410 and 1230 respectively. If the current in primary is 6 A, then that in the secondary coil is :

(a) 12 A
(b) 2 A
(c) 1 A
(d) 18 A
Puducherry TnboardTamil Nadu HSC (DGE) Board 2025MCQ· 1mImportance★★★★★
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Using the transformer current relation IsNs=IpNpI_sN_s=I_pN_p with Np=410N_p=410, Ns=1230N_s=1230, Ip=6I_p=6 A gives Is=2I_s=2 A.

Working

For an ideal transformer, the turns and currents in primary/secondary satisfy

IpNp=IsNs ⇒ Is=IpNpNsI_pN_p = I_sN_s \ \Rightarrow\ I_s = I_p\dfrac{N_p}{N_s}

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