Evaluation · Q13
Q.A marriage between a colourblind man and a normal woman produces
(a) All carrier daughters and normal sons
(b) 50% carrier daughters, 50% normal daughters
(c) 50% colourblind sons, 50% normal sons
(d) All carrier offsprings
Puducherry TnboardTextbookSubjectiveImportance★★★★★
19% · 13/68 Questions
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Start your 14-day free trial to unlock the full solution →Step 1. Write the genotypes: colourblind man = XcY; normal-visioned woman, with no indication she is a carrier, = XCXC (homozygous normal).
Step 2. List gametes: father gives Xc or Y; mother gives only XC (she has no Xc to give).
Step 3. Cross the gametes: XC(mother) x Xc(father) → XCXc, every daughter is a carrier but has normal vision (XC is dominant); XC(mother) x Y(father) → XCY, every son has normal vision and carries no colourblindness allele at all (his only X came from his normal mother). …
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