NCERT Exemplar · Q37
Q.Phenyl benzoate, C6H5-O-CO-C6H5 (the benzoate ester of phenol), is treated with NaOH solution. Identify the product(s). (Two or more options may be correct.)
(i) Phenol
(ii) Sodium phenoxide
(iii) Sodium benzoate
(iv) Benzophenone
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Start your 14-day free trial to unlock the full solution →Alkaline hydrolysis of phenyl benzoate gives sodium benzoate (from the acyl part) and phenol; because phenol is acidic, NaOH converts it to sodium phenoxide. So the isolated products are sodium benzoate (iii) and sodium phenoxide (ii).
Concept
Esters undergo base-promoted hydrolysis (saponification): hydroxide attacks the carbonyl carbon, and the ester breaks to give the carboxylate anion and the alkoxide/phenoxide (or free alcohol).
Steps
- OH(-) attacks the carbonyl carbon of C6H5-CO-O-C6H5; the C-O bond to the phenyl breaks.
- Products of hydrolysis: benzoate ion (C6H5COO-) and phenol (C6H5OH).
- Benzoate becomes sodium benzoate, C6H5COO(-)Na(+).
- Phenol (pKa about 10) is acidic enough to be deprotonated by NaOH, so it is obtained as sodium phenoxide, C6H5O(-)Na(+).
Overall
C6H5-O-CO-C6H5 + 2 NaOH --> C6H5COO(-)Na(+) + C6H5O(-)Na(+) + H2O …
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