Q.Which is most basic

Amine Basicity Order – From Intuition to Precision

You already know that a base is something that accepts a proton ($H^+$). An amine does this through the lone pair on its nitrogen. The more readily that lone pair grabs a proton, the stronger the base. So the question becomes: what makes that lone pair more or less willing to accept a proton?

The answer depends on three competing effects: inductive effect (electron pushing/pulling from nearby groups), steric hindrance (bulky groups blocking the proton), and solvation (how water molecules stabilise the protonated amine). And critically, the order flips depending on whether you are in the gas phase or in water.

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The Intuition – What Would You Expect?

Imagine a nitrogen with three hydrogens: ammonia ($NH_3$). Now replace one hydrogen with a methyl group ($CH_3$). Methyl is an electron-donating group — it pushes electron density toward the nitrogen. That makes the lone pair richer, so it should grab a proton more easily. So methylamine ($CH_3NH_2$) should be a stronger base than ammonia.

Replace another hydrogen with a second methyl group. Now you have dimethylamine ($(CH_3)_2NH$). Even more electron density on nitrogen — stronger base still. Replace the third hydrogen: trimethylamine ($(CH_3)_3N$). Maximum electron donation — so you would expect it to be the strongest base of all.

That is the inductive effect prediction: more alkyl groups → stronger base. In the gas phase, this is exactly what happens. The order is:

Gas phase: $NH_3 < 1^\circ < 2^\circ < 3^\circ$

But in water, the observed order is different. Why?

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The Complication – Solvation and Steric Hindrance

When an amine accepts a proton, it becomes a positively charged ammonium ion ($RNH_3^+$). In water, that positive charge is stabilised by hydrogen bonding with water molecules. The more hydrogens on the nitrogen, the more hydrogen bonds it can form — and the more stable the protonated form becomes.

A primary amine ($1^\circ$) has three N–H hydrogens after protonation. A secondary ($2^\circ$) has two. A tertiary ($3^\circ$) has only one. So solvation stabilises the protonated form in the order: $1^\circ > 2^\circ > 3^\circ$.

At the same time, bulky alkyl groups physically block the approach of a proton to the nitrogen — this is steric hindrance. A tertiary amine has three bulky groups crowding the nitrogen, making it harder for $H^+$ to reach the lone pair.

So in water, two effects oppose the inductive effect: solvation (which favours more N–H bonds) and steric hindrance (which favours less crowding). The result is a compromise.

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The Precise Statement – Aqueous Phase Order

In water, the typical order of basic strength for aliphatic amines is:

Aqueous phase: $NH_3 < 3^\circ < 1^\circ < 2^\circ$

That is, secondary amines are the strongest bases in water, followed by primary, then tertiary, then ammonia.

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The Full Picture – A Table