Exercises · Q13
Q.How does the procedure of drawing a histogram differ when class intervals are unequal in comparison to equal class intervals in a frequency table?
Rajasthan RbseTextbookSubjective· 3mImportance★★★★★est
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Start your 14-day free trial to unlock the full solution →For equal intervals, plot the frequency directly as the height. For unequal intervals, first convert each frequency into an adjusted frequency (frequency density) and use that as the height, so that area — not height — stays proportional to frequency.
Concept first: in a histogram, area represents frequency
A histogram is built on one rule: the area of each rectangle is proportional to the class frequency. When class intervals (widths) are all equal, area ∝ height, so we can simply plot the frequency as the height. The moment widths become unequal, this shortcut breaks — a wide class would get an unfairly large area for the same frequency.
Equal class intervals
- All rectangles have the same width.
- Height = class frequency, plotted directly.
- Rectangles are drawn adjacent, with no gaps.
Unequal class intervals
- Widths differ, so raw frequencies cannot be used as heights.
- Compute an adjusted frequency (frequency density) for each class:
- Draw each rectangle at this adjusted height over its actual width. …
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