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Worked Examples · Example 29

Q.Calculate the Quartile deviation of following observations: 15, 20, 22, 28, 35, 27, 44, 48, 50, 55, and 60.

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Sort the 11 observations, locate the first quartile Q1Q_1 and third quartile Q3Q_3 by position, and take half their difference.

[!FORMULA] QD=Q3−Q12QD=\dfrac{Q_3-Q_1}{2}

where Q1Q_1 = value at position n+14\dfrac{n+1}{4}, Q3Q_3 = value at position 3(n+1)4\dfrac{3(n+1)}{4}, in the data sorted ascending, nn = number of observations.

  1. List the data: 15,20,22,28,35,27,44,48,50,55,6015,20,22,28,35,27,44,48,50,55,60

  2. Arrange in ascending order:

    15, 20, 22, 27, 28, 35, 44, 48, 50, 55, 6015,\ 20,\ 22,\ 27,\ 28,\ 35,\ 44,\ 48,\ 50,\ 55,\ 60

  3. Count the observations: n=11n=11.

  4. Locate Q1Q_1's position: n+14=124=3\dfrac{n+1}{4}=\dfrac{12}{4}=3rd value.

    Counting: 1st=15=15, 2nd=20=20, 3rd=22\mathbf{3rd=22}

    Q1=22Q_1=22

  5. Locate Q3Q_3's position: 3(n+1)4=3×124=9\dfrac{3(n+1)}{4}=\dfrac{3\times12}{4}=9th value.

    Counting: …, 7th=44=44, 8th=48=48, 9th=50\mathbf{9th=50}

    Q3=50Q_3=50

  6. Apply the formula:

    QD=Q3−Q12=50−222=282=14QD=\dfrac{Q_3-Q_1}{2}=\dfrac{50-22}{2}=\dfrac{28}{2}=14

  7. Self-check: 22+2(14)=22+28=50=Q322+2(14)=22+28=50=Q_3 ✓

✓Final answer

Quartile Deviation =14=14

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