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Worked Examples · Example 2

Q.Find 'x' and 'y' if (x2−4x, y2−y)=(−4,6)(x^2 - 4x,\ y^2 - y) = (-4, 6)

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Equating components of the ordered pair (x2−4x, y2−y)=(−4,6)(x^2-4x,\ y^2-y)=(-4,6) and factoring the resulting quadratics gives x=2x=2 and y=3y=3 or y=−2y=-2.

Equality of ordered pairs: (a,b)=(c,d)⇒a=c, b=d(a,b)=(c,d)\Rightarrow a=c,\ b=d. Quadratics are solved by bringing all terms to one side and factoring: t2+pt+q=0⇒(t−r1)(t−r2)=0t^2+pt+q=0\Rightarrow (t-r_1)(t-r_2)=0.

  1. Equate the first components.

x2−4x=−4x^2-4x=-4

  1. Bring to standard form and factor.

x2−4x+4=0 ⇒ (x−2)2=0x^2-4x+4=0\ \Rightarrow\ (x-2)^2=0

  1. Solve for xx (repeated root).

x−2=0 ⇒ x=2x-2=0\ \Rightarrow\ x=2

  1. Equate the second components.

y2−y=6y^2-y=6

  1. Bring to standard form and factor. …

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