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Worked Examples · Example 18

Q.Out of 500 car owners investigated, 400 owned car A and 200 owned car B, 50 owned both A and B cars. Is the data correct?

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Apply the union formula to the given numbers; if the resulting union exceeds the total surveyed, the data is inconsistent.

n(A∪B)=n(A)+n(B)−n(A∩B)n(A\cup B)=n(A)+n(B)-n(A\cap B), and it must always satisfy n(A∪B)≤Total surveyedn(A\cup B)\le \text{Total surveyed}.

  1. Given: total surveyed =500=500, n(A)=400n(A)=400, n(B)=200n(B)=200, n(A∩B)=50n(A\cap B)=50.
  2. Compute the number who own at least one car (A or B): n(A∪B)=n(A)+n(B)−n(A∩B)=400+200−50=550n(A\cup B)=n(A)+n(B)-n(A\cap B)=400+200-50=550.
  3. Compare with the total investigated: n(A∪B)=550>500=Totaln(A\cup B)=550 > 500=\text{Total}.
  4. Since the number of people owning at least one of the two cars cannot exceed the total number of people surveyed, this is a contradiction. …

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