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Exercise 3.4 · Q2

Q.In a group of 65 people, 40 like cricket, 10 like both cricket and tennis. How many like tennis only? How many like tennis.

Sikkim CbseNCERTSubjective· 2mImportance★★★★★est
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With everyone in the group liking cricket, tennis, or both, subtract the 'both' and 'cricket-only' counts from the total to isolate 'tennis-only', then add back 'both' for the tennis total.

Inclusion–exclusion: n(C∪T)=n(C)+n(T)−n(C∩T)n(C\cup T) = n(C) + n(T) - n(C\cap T). Cricket-only =n(C)−n(C∩T)= n(C) - n(C\cap T); Tennis-only =n(T)−n(C∩T)= n(T) - n(C\cap T).

  1. Given: total people n(C∪T)=65n(C\cup T) = 65, cricket-lovers n(C)=40n(C) = 40, both n(C∩T)=10n(C\cap T) = 10.

  2. Find cricket-only: n(C)−n(C∩T)=40−10=30n(C) - n(C\cap T) = 40 - 10 = 30 people like cricket only.

  3. Find tennis-only using the total: the group splits into cricket-only, tennis-only, and both: 65=30+(tennis-only)+1065 = 30 + \text{(tennis-only)} + 10.

    Tennis-only=65−30−10=25\text{Tennis-only} = 65 - 30 - 10 = 25.

  4. Find total tennis-lovers: n(T)=tennis-only+both=25+10=35n(T) = \text{tennis-only} + \text{both} = 25 + 10 = 35.

  5. Check with the inclusion–exclusion formula: n(C∪T)=n(C)+n(T)−n(C∩T)=40+35−10=65n(C\cup T) = n(C)+n(T)-n(C\cap T) = 40+35-10 = 65. ✓ Matches the given total.

✓Final answer

Tennis only =25= 25 people; total tennis-lovers =35= 35 people.

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