Skip to content
NCERT Exemplar · Q24

Q.In which of the following options order of arrangement does not agree with the variation of property indicated against it? (Note: more than one of the given options may be correct.)

(i) Al^3+ < Mg^2+ < Na^+ < F^- (increasing ionic size)
(ii) B < C < N < O (increasing first ionisation enthalpy)
(iii) I < Br < Cl < F (increasing electron gain enthalpy)
(iv) Li < Na < K < Rb (increasing metallic radius)
Sikkim CbseMCQ· 1mImportance★★★★★est
68% · 74/109 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

The key is to check each sequence against the actual periodic trend for the stated property. Options (B) and (C) contain errors: (B) breaks the ionization enthalpy trend at N→O, and (C) reverses the correct electron gain enthalpy order. The correct answer is B and C.

Let’s go through each option one by one, with the reasoning rooted in periodic trends.

  1. Option (A): Al³⁺ < Mg²⁺ < Na⁺ < F⁻ (increasing ionic size)

    All four species are isoelectronic — they each have 10 electrons (like Ne). For isoelectronic ions, ionic radius decreases as nuclear charge (Z) increases, because the same electron cloud is pulled in more strongly.

    • Nuclear charges: Al³⁺ (Z=13), Mg²⁺ (Z=12), Na⁺ (Z=11), F⁻ (Z=9).
    • So the order of increasing size is: smallest Z → largest size, i.e., Al³⁺ < Mg²⁺ < Na⁺ < F⁻. This matches the given order perfectly. So (A) is correct.
  2. Option (B): B < C < N < O (increasing first ionisation enthalpy)

    First ionisation enthalpy generally increases across a period (left to right) because nuclear charge increases and atomic radius decreases, making it harder to remove an electron.

    • B (Z=5) < C (Z=6) < N (Z=7) is correct.
    • But N has a half-filled 2p³ subshell (extra stability), so its ionisation enthalpy is actually higher than that of O. The correct order is B < C < O < N. The given order B < C < N < O is therefore wrong. So (B) does not agree.
  3. Option (C): I < Br < Cl < F (increasing electron gain enthalpy)

    Electron gain enthalpy (often called electron affinity) becomes more negative (more energy released) as we go up a group, because the atom is smaller and the incoming electron feels a stronger attraction. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.