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NCERT Exemplar · Q5

Q.The electronic configuration of gadolinium (Atomic number 64) is

(i) [Xe] 4f^3 5d^5 6s^2
(ii) [Xe] 4f^7 5d^2 6s^1
(iii) [Xe] 4f^7 5d^1 6s^2
(iv) [Xe] 4f^8 5d^6 6s^2
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Gadolinium achieves extra stability through a half-filled 4f74f^7 subshell combined with the minimum occupancy needed in higher orbitals. The configuration is [Xe] 4f74f^7 5d15d^1 6s26s^2.

The electronic configuration of lanthanides is governed by the interplay between orbital energies and the exceptional stability of half-filled and fully-filled subshells. For gadolinium, this stability principle creates a striking departure from the naive filling order.

Why half-filled ff subshells matter

The 4f4f subshell can hold 14 electrons across seven orbitals. When exactly half-filled (4f74f^7), each of the seven orbitals contains one electron with parallel spin. This arrangement minimizes electron-electron repulsion (exchange energy is maximized) and creates unusual stability—similar to the half-filled d5d^5 configuration you see in chromium and manganese.

For lanthanides around the middle of the series, the energy cost of promoting an electron from 6s6s or 5d5d into 4f4f can be offset by the stability gained from achieving 4f74f^7.

Working through gadolinium's configuration

  1. Start with xenon core: Gadolinium (atomic number 64) has 64 electrons. The xenon core [Xe] accounts for 54 electrons, leaving 10 more to place.

  2. Expected filling order: Naively, after [Xe] we fill 4f4f before 5d5d (since 4f4f is lower in energy for lanthanides). We'd expect to place electrons as 6s26s^2 first (2 electrons), then 4f84f^8 (8 electrons), giving [Xe] 4f84f^8 6s26s^2.

  3. Stability check: But 4f84f^8 is one electron past the half-filled 4f74f^7 configuration. The system can gain significant exchange energy by keeping 4f74f^7 instead.

  4. Redistribution: To achieve 4f74f^7 while accounting for all 10 electrons beyond xenon:

    • Place 4f74f^7 (7 electrons) — half-filled, maximum stability
    • Place 6s26s^2 (2 electrons) — the 6s6s orbital fills early and remains occupied
    • Place 5d15d^1 (1 electron) — the "extra" electron goes here rather than making 4f84f^8 …

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