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Write Brief Answer · Q27

Q.A tank contains a mixture of 52.5 g of oxygen and 65.1 g of CO2_2 at 300 K. The total pressure in the tank is 9.21 atm. Calculate the partial pressure (in atm.) of each gas in the mixture.

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Step 1. Convert masses to moles. O2_2 (M = 32): nO2=52.532=1.6406 moln_{O_2}=\dfrac{52.5}{32}=1.6406\ \text{mol}. CO2_2 (M = 44): nCO2=65.144=1.4795 moln_{CO_2}=\dfrac{65.1}{44}=1.4795\ \text{mol}.

Step 2. Total moles =1.6406+1.4795=3.1202 mol=1.6406+1.4795=3.1202\ \text{mol}.

Step 3. Mole fractions: xO2=1.64063.1202≈0.5258x_{O_2}=\dfrac{1.6406}{3.1202}\approx0.5258; xCO2=1.47953.1202≈0.4742x_{CO_2}=\dfrac{1.4795}{3.1202}\approx0.4742. …

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