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Choose the Best Answer · Q15

Q.If temperature and volume of an ideal gas is increased to twice its values, the initial pressure P becomes

(a) 4P
(b) 2P
(c) P
(d) 3P
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Step 1. From the ideal gas equation, P=nRTVP=\dfrac{nRT}{V}.

Step 2. If both T and V are doubled (to 2T2T and 2V2V, with n fixed), the new pressure is Pnew=nR(2T)2V=nRTV=PP_{new}=\dfrac{nR(2T)}{2V}=\dfrac{nRT}{V}=P. …

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