Q.Explain the following, give appropriate reasons.
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Start your 14-day free trial to unlock the full solution →Step 1 (i). Nitrogen's configuration is exactly half-filled, an extra-stable arrangement; oxygen's has one pair of electrons in the same orbital, adding extra electron-electron repulsion that makes its electron comparatively easier to remove. So , even though O has one more proton.
Step 2 (ii). For IE1, carbon () simply has a higher nuclear charge than boron () with no anomaly favouring boron, so follows the normal trend. For IE2: removing a second electron takes (, filled and stable) to -- breaking a stable filled subshell -- while it takes (, an ordinary, not-yet-stable configuration much like boron's own ground state) to , an easier removal. So for the SECOND ionisation the comparison reverses: .
Step 3 (iii). Be () and Mg (/) already have a completely filled outer s-subshell; adding an electron would have to enter a new, higher-energy subshell, which is unfavourable, giving near-zero electron affinity. N () and P () have an exactly half-filled p-subshell; adding an electron would pair up an electron in an already-stable, symmetric arrangement, which is also unfavourable (though slightly less so for P, whose larger 3p orbital has less electron-electron repulsion than N's compact 2p), giving very low (but slightly higher than Be/Mg) electron affinity. …
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