Skip to content
Choose the Best Answer · Q1

Q.What would be the IUPAC name for an element with atomic number 222?

(a) bibibiium
(b) bididium
(c) didibium
(d) bibibium
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
2% · 1/62 Questions
✓ Free question

Step 1. Split the atomic number into its individual digits: 222 -> 2, 2, 2.

Step 2. Look up the IUPAC root for each digit (Table 3.8): 2 -> "bi". So all three digits give the root "bi", in order: bi + bi + bi.

Step 3. Concatenate the roots and add the suffix "-ium": bi + bi + bi + ium = "bibibium". None of the elision rules (Rule 3) apply here, since the join is bi+bi (not bi/tri immediately before ium at the very last join only) -- only the final bi before ium elides its trailing "i": bi-bi-bi-ium -> the last bi's "i" merges with "ium", giving "bibibium" exactly as in option (d).

✓Final answer

(d) bibibium

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.